To cater the stresses and loads in RCC, Bars are bent to different shapes in the bar bending schedule.

Different shapes of bars have different cutting length. In this post, we are going to explain you about “How to calculate or find the cutting length of Stirrups for different shapes”.

Remember,

The transverse reinforcement provided in Column is called **Ties** and the transverse reinforcement provided in Beam is called **Stirrups**. But on-site, we usually call both transverse reinforcements as Stirrups.

The prime reason for providing the stirrups in the beam is for shear requirements and to keep the longitudinal bars in position. If you wanted to know more about the why stirrups & ties provided in the beam and column you can** refer here**

Deducting the concrete cover is most important in Bar bending, if you dont know how to deduct the concrete cover then refer this post

**Concrete Cover deductions in Beams, Columns, Slab, Footings**

Contents

- Steps involved in finding the cutting length of stirrups:-
- Typical Diagram of Stirrup:-
- Important standards used in Bends & Hooks:
- Cutting length for Rectangular Stirrups:-
- Cutting length for Square Stirrups:-
- Cutting Length for Circular Stirrup:
- Cutting Length for Triangular Stirrups:
- Cutting Length for Diamond Stirrups:

# Steps involved in finding the cutting length of stirrups:-

- Look at the size of column or beam from drawings
- Adopt Dia of the bar (generally 8mm Dia is used for stirrups)
- Deduct the concrete cover or clear cover
- Find the total outer length of stirrup after deducting concrete cover.
- Add the length of the hook to the length of the stirrup
- Deduct the length of bends
- Use below formula to find the total cutting length of stirrups

Formula:

Cutting Length of Stirrups = Perimeter of Shape + Total hook length – Total Bend Length

**Important Basic formulas:**

Perimeter of Rectangle = 2 ( length + breadth)

Perimeter of Square = 4 x side length

Perimeter of circle or Circumference of Circle = 2πr = πd (r= radius, d= Diameter of Circle)

## Typical Diagram of Stirrup:-

Refer the below image of the typical diagram of stirrup for clear understanding about x & y length, bends, hooks and concrete cover.

In the above image, there are 5 bends at 4 corners, 2 hooks and concrete cover around the stirrup.

x = length of the stirrup in the x-direction after deducting concrete cover &

y = length of the stirrup in the y-direction after deducting concrete cover.

## Important standards used in Bends & Hooks:

The below standards are most important in calculating the hook length and bend lengths at corners while finding cutting length of stirrups.

- 1 Hook length = 9d or 75mm
- 45° Bend length = 1d
- 90° Bend length = 2d
- 135° Bend length = 3d

Remember, **d = Diameter of Bar**

## Cutting length for Rectangular Stirrups:-

Rectangular column or rectangular beam is the most commonly used shape of the column in any construction. In this shape of beam or column, a rectangular stirrup is usually adopted.

- Considering the below Rectangular column size 230mm x 450mm for calculation purpose

- Adopting Dia of Bar used for stirrups is 8mm
- Deducting the concrete cover 20mm from all sides

x = 230 – 20-20 = 190mm

y = 450-20-20 = 410mm

**Total Length of the hooks:**

From fig, There are two hooks which means 9d+9d = 18d**Total Length of Bends:**

From above fig, There are 3 bends which are bent at an angle of 90^{0}and two bends are bent at an angle of 135^{0}

Total bend length = 3 x 90^{0}Bend length + 2 x 135^{0}Bend length = 3 x 2d + 2 x 3d = 12d = 12 x 8 = 96mm

*Total Cutting length of Rectangular Stirrup = Perimeter of Rectangle + Total Hook length – Total Bend Length*

*= 2 (x+y) +18d – 12d = 2(190 + 410) + 18 x 8 – 12 x 8 = 1248mm = 1.248m*

## Cutting length for Square Stirrups:-

- Considered the column size as 450mm x 450mm

- Adopting Dia of Bar used for stirrups is 8mm
- Deducting the concrete cover 25mm from all sides (in square all sides are equal)

x = 450- 20-20 = 410mm

y = 450-20-20 = 410mm, Hence x = y (in square all sides are equal)

**Total Length of the hook:**

There are two hooks which mean 9d+9d = 18d**Total length of Bends:**

There are 3 bends which are bent at an angle of 90^{0}and one is bent at an angle of 135^{0}.

Total bend length = 3 x 90^{0}Bend length + 2 x 135^{0}Bend length = 3 x 2d + 2 x 3d = 12d = 12 x 8 = 96mm

*Total Cutting length of Square Stirrup = Perimeter of Square + Total Hook length – Total Bend Length*

*= 4 x 410 +18d – 12d = 1648mm = 1.64m*

## Cutting Length for Circular Stirrup:

- Considered the column dia as D = 1000mm
- Adopting Dia of Bar used for stirrups is d =8mm

- Deducting the concrete cover from diameter of column

D = 1000-25-25 = 950mm

- Circumference length of Ring = πD = 950 x 3.14 = 2983mm
**Total Length of the hook:**

There are two hooks which means 9d+9d= 18d**Total Length of Bends:**

There are 2 bends which are bent at an angle of 135^{0}

Total bend length = 2 x 135^{0}Bend length = 2 x 3d = 6d= 6 x 8 = 48mm

*Total Cutting length of Circular Stirrup or Ring = Circumference of Circle + Total Hook length – Total Bend Length *

*= 2983 +18d – 6d =3079mm =*

**3.07m**

## Cutting Length for Triangular Stirrups:

- Considered the Column size 400mm x 450mm

- Adopting Dia of Bar used for stirrups is d = 8mm
- Deducting the concrete cover 25mm from all sides

x = 400-20-20 = 360mm

y = 450-20-20 = 410mm

From Pythagorean theorem,

**Hypotenuse**^{2}=(Opposite)^{2}+ (Adjacent)^{2}

look at 2nd triangle in above image

H^{2}=(x/2)^{2}+ y^{2}

H^{2}=180^{2}+ 410^{2}=> = √(447)^{2}= 447mm

The total length of stirrup till now = 2 x H + 360 = 2 x 447 + 360 = 1254mm **Total Length of the hooks:**

There are two hooks which means 9d+9d= 18d

**Total length of Bends:**

There are 4 bends which are bent at an angle of 135^{0}

Total bend length =4 x 135^{0}Bend length= 4 x 3d = 12d= 12 x 8 = 96mm

*Total Cutting length of Triangular Stirrup = Perimeter of Triangle + Total Hook length – Total Bend Length*

*= 1254+18d – 12d = 1302mm = 1.3m*

## Cutting Length for Diamond Stirrups:

- Considered the Column size 400mm x 400mm

- Adopting Dia of Bar used for stirrups is d = 8mm
- Deducting the concrete cover 25mm from all sides

x = 400-20-20 = 360mm

y = 400-20-20 =360mm

From Pythagorean theorem,

**Hypotenuse**^{2}=(Opposite)^{2}+ (Adjacent)^{2}

H^{2}=(x/2)^{2}+( y/2)^{2}

H^{2}=180^{2}+ 180^{2}=> = √(254)^{2}= 254mm - The total length of stirrup = 4 x H =4 x 254 = 1016mm
**Total Length of the hook:**

There are two hooks which means 9d+9d= 18d**Total length of Bends:**

There are 3 bends which are bent at an angle of 90^{0 }+ 2 bends which are bent at an angle of 135^{0}

Total bend length = 3 x 90^{0}Bend length + 2 x 135^{0}Bend length= 3 x 2d + 2 x 3d = 12d = 12 x 8 = 96mm

*Total Cutting length of Diamond Stirrup = Perimeter of Diamond shape + Total Hook length – Total Bend Length *

*= 1016+144-96 = 1064mm =*

**1.064mm**I hope now you can easily find the cutting length for different types of stirrups.

If you have any doubts you can post them on our **Forum**

This is brilliant

Thank u for the teaching to all viewers ,that tend to add on the impact to those who has taken long while missing the field works.

For calculation on my side is not abig problem I quantify it proper.

For finding the hook length and bend length, the ‘d’ used here is dia of steel for making stirrups.(8mm here)

In actual the dia of the steel(vertical steel provided) on which the ring/stirrup is the touching has to be used(12mm 16mm 20mm as per drawing spec) , as the size of column steel differs the bend length and hook length will be changed.

well